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From energy conservation,

$21 mv_{A}+(PE)_{A}=21 mv_{B}+(PE)_{B}$

Since speed does not change from A to B, KE remains same.

Distance of the particle at A and B is equal to the radius of the the circle.

$PE=−RGMm $

Hence, $(PE)_{A}=(PE)_{B}$

Hence, work done is zero as there is no change in total energy E from A to B.

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